8y^2-129y+16=0

Solution for 8y^2-129y+16=0 equation:

8y^2-129y+16=0

a = 8; b = -129; c = +16;
Δ = b2-4ac
Δ = -1292-4·8·16
Δ = 16129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16129}=127$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-129)-127}{2*8}=\frac{2}{16}
=1/8
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-129)+127}{2*8}=\frac{256}{16}
=16
$